Suppose that on average every hour 10 customers enter a departmental store.
a. Calculate the probability that in an hour 12 customers entered the Store.
Solution:
λ=10\lambda=10λ=10
Let XXX be the random variable denoting the number of customers per hour.
X∼Poisson(λ)X\sim Poisson(\lambda)X∼Poisson(λ)
P(X=12)=e−10(10)1212!=0.09478P(X=12)=\dfrac{e^{{-10}}({10})^{12}}{12!}=0.09478P(X=12)=12!e−10(10)12=0.09478
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