Find each of the following percentile points and draw the appropriate normal
curve. Complete your procedures.
1. Find the 99th percentile of the normal curve.
2. Find the upper 5% of the normal curve.
3. The results of the entrance examination for freshmen are normally distributed
with 𝑥 = 85 and 𝑠 = 12.5. What is the percentile rank of a score of 92?
1.
z-score is 2.33 for 99 percentile
2.
z-score = 1.65
3.
Since "\\mu=85" and "\\sigma =12.5" we have:
"P (X>92) = P(X-\\mu>92-85) = P(\\dfrac{X-\\mu}{\\sigma}>\\dfrac{92-85}{12.5})"
Since "\\dfrac{X-\\mu}{\\sigma}" and "\\dfrac{92-85}{12.5}" = 0.56 we have:
P(X > 92) = P(Z > 0.56)
Use the standard normal table to conclude that
P(Z > 0.56) = 0.2877
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