A random sample of n = 60 measurements is obtained from a population with μ = 192 and σ 43. Describe the sampling distribution for the sample means by computing the μx and σx.
μx=μ=192σx=σn=4360=5.55μ_x = μ = 192 \\ σ_x = \frac{σ}{\sqrt{n}} = \frac{43}{\sqrt{60}} = 5.55μx=μ=192σx=nσ=6043=5.55
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