Null hypothesis "H_0:\\mu=85."
Alternative hypothesis "H_a:\\mu<85."
Test statistic: "z=\\frac{\\bar x-\\mu}{\\frac{\\sigma}{\\sqrt{n}}}=\\frac{83.20-85}{\\frac{8}{\\sqrt{50}}}=-1.59."
P-value: "p=P(Z<-1.59)=0.0559."
Since the P-value is greater than 0.05, fail to reject the null hypothesis.
There is no evidence to show that this group has a lower performance than the ones in general at 0.05 significance level.
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