a)
Sample size N=76.
x=N1∑xinixi — value (Young’s modulus)ni — corresponding frequencys=N1∑(xi−x)2ni
b)
Sample size N=85.
pn(x)={N⋅hlj,x∈[a+jh,a+(j+1)h)0, x∈/(a,b)lj — number of values in the interval [a+jh,a+(j+1)h)
h=30
xi∗=2xi+xi−1s=N1∑(xi∗)2ni−(N1∑xi∗ni)2x=N1∑xi∗ni
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