F(x,y)={k(1-x^2) find the value of k
Since f(x) is a p.d.f. ∫∞∞f(x)dx=1\int_{\infty}^{\infty} f(x)dx=1∫∞∞f(x)dx=1
⟹ ∫01k(1−x2)dx=1\implies \int_0^1 k(1-x^2)dx=1⟹∫01k(1−x2)dx=1
⟹ k(x−x33)01=1\implies k(x-\dfrac{x^3}{3})_0^1=1⟹k(x−3x3)01=1
⟹ k(1−13)=1\implies k(1-\dfrac{1}{3})=1⟹k(1−31)=1
⟹ k=32\implies k=\dfrac{3}{2}⟹k=23
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