Question #171283

F(x,y)={k(1-x^2) find the value of k



1
Expert's answer
2021-03-16T05:03:40-0400

Since f(x) is a p.d.f. f(x)dx=1\int_{\infty}^{\infty} f(x)dx=1


    01k(1x2)dx=1\implies \int_0^1 k(1-x^2)dx=1


    k(xx33)01=1\implies k(x-\dfrac{x^3}{3})_0^1=1


    k(113)=1\implies k(1-\dfrac{1}{3})=1


    k=32\implies k=\dfrac{3}{2}



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