A bottler of drinking water fills plastic bottles with a mean volume of 1,000 milliliters (mL) and standard deviation of 7. The fill volumes are normally distributed. What is the probability that a bottle has a volume between 996ml and 1,002ml?
μ=1000 mLσ=7P(996<X<1002)=P(996−10007<Z<1002−10007)=P(−0.571<Z<0.285)=P(Z<0.285)−P(Z<−0.571)=0.6121−0.2839=0.3282μ = 1000 \; mL \\ σ = 7 \\ P(996 < X < 1002) = P(\frac{996-1000}{7}<Z< \frac{1002-1000}{7}) \\ = P(-0.571<Z<0.285) \\ = P(Z<0.285) -P(Z<-0.571) \\ = 0.6121 -0.2839 \\ = 0.3282μ=1000mLσ=7P(996<X<1002)=P(7996−1000<Z<71002−1000)=P(−0.571<Z<0.285)=P(Z<0.285)−P(Z<−0.571)=0.6121−0.2839=0.3282
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