Use the z-table to find the area under the normal curve that is located between z=0 and each of the following.
AREA
1.z=0.56
2.z=1.32
3.z=1.05
4.z=-2.18
5.z=2.58
S = f(z) - 0.5
1. f(0.56) = 0.71226, S = 0.71226 - 0.5 = 0.21226
2. f(1.32) = 0.90658, S = 0.90658 - 0.5 = 0.40658
3. f(1.05) = 0.85314, S = 0.85314 - 0.5 = 0.35314
4. f(-2.18) = 0.01463, S = 0.5 - 0.01463 = 0.48537
5. f(2.58) = 0.99506, S = 0.99506 - 0.5 = 0.49506
Comments
Leave a comment