What sample size should be obtained to determine a 94% confidence within 4%?
Sample size formula:
"n = \\frac{Z_{\u03b1\/2}^2 pq}{E^2}"
P unknown:
"n = \\frac{Z_{\u03b1\/2}^2 0.25}{E^2}"
Determine "Z_{\u03b1\/2}" for confidence level of 94% using table:
"Z_{0.03} = 1.89"
"n = \\frac{1.89^2 \\times 0.25}{0.04^2} = \\frac{0.893}{0.0016} = 558"
Answer: 558
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