What sample size should be obtained to determine a 94% confidence within 4%?
Sample size formula:
n=Zα/22pqE2n = \frac{Z_{α/2}^2 pq}{E^2}n=E2Zα/22pq
P unknown:
n=Zα/220.25E2n = \frac{Z_{α/2}^2 0.25}{E^2}n=E2Zα/220.25
Determine Zα/2Z_{α/2}Zα/2 for confidence level of 94% using table:
Z0.03=1.89Z_{0.03} = 1.89Z0.03=1.89
n=1.892×0.250.042=0.8930.0016=558n = \frac{1.89^2 \times 0.25}{0.04^2} = \frac{0.893}{0.0016} = 558n=0.0421.892×0.25=0.00160.893=558
Answer: 558
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