a class of 30 of these pupils is used as sample. what is the probability that the class mean is greater than 46 inches?
Given,
Mean μ=45\mu=45μ=45
Standard deviation σ=2\sigma=2σ=2
Probability that the class mean is greater than 46 =P(X>46)P(X>46)P(X>46)
z=x−μσ=46−452=12=0.5z=\dfrac{x-\mu}{\sigma}=\dfrac{46-45}{2}=\dfrac{1}{2}=0.5z=σx−μ=246−45=21=0.5
Therefore the required probability is P(z>0.5)=P(0<z<∞)−P(0<z<0.5)P(z>0.5)=P(0<z<\infty)-P(0<z<0.5)P(z>0.5)=P(0<z<∞)−P(0<z<0.5)
=0.5−0.1915=0.3085=0.5-0.1915=0.3085=0.5−0.1915=0.3085
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