Question #168665

determine a 95% confidence interval for the mean of a normal population with variance 6.25


Expert's answer

Standart deviation S = 6.25\sqrt{6.25} = 2.5

From the standard normal (Z-) distribution, z*-value of confidence level 95% is 1.96

xˉ±1.96σn\bar{x} ±1.96\frac{\sigma}{\sqrt{n}}


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