Answer to Question #168451 in Statistics and Probability for karel manlangit

Question

In how many ways can you form a four-digit number greater than or equal to 6000 using the digits 0,3,5,6,7, and 8 if repetition of digits is NOT allowed? 

Answer 1

The first digit must be 6, 7 or 8.

Number of permutations from 5 by 3: $P_5^3=\frac{5!}{(5-3)!}=60.$

Number of ways: $N=60*3=180.$