From a box containing 2 apples, 2 peaches and 2 oranges, 3 fruits are drawn at
random. Let P be a random variable representing the number of oranges that occur. Construct a probability distribution.
P(X=0)=46∗35=25.P(X=0)=\frac{4}{6}*\frac{3}{5}=\frac{2}{5}.P(X=0)=64∗53=52.
P(X=1)=26∗45+46∗25=815.P(X=1)=\frac{2}{6}*\frac{4}{5}+\frac{4}{6}*\frac{2}{5}=\frac{8}{15}.P(X=1)=62∗54+64∗52=158.
P(X=2)=26∗15=115.P(X=2)=\frac{2}{6}*\frac{1}{5}=\frac{1}{15}.P(X=2)=62∗51=151.
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