Question #168233

The probabilities of a machine manufacturing 0, 1, 2, 3, 4, or 5defective parts in one day are 0.75, 0.17, 0.04, 0.025, 0.01, and 0.005, respectively. The computed variance is _____ and standard deviation is _____ of the distribution.

NOTE: Round off your answer to the nearest hundredths


1
Expert's answer
2021-03-03T04:22:10-0500

The expected value μ=0×0.75+1×0.17+2×0.04+3×0.025+4×0.01+5×0.005μ = 0 \times 0.75 + 1 \times 0.17 + 2 \times 0.04 + 3 \times 0.025 + 4 \times 0.01 + 5 \times 0.005

=0+0.17+0.08+0.075+0.04+0.025=0.39= 0 + 0.17 + 0.08 + 0.075 + 0.04 + 0.025 \\ = 0.39

Variance:

σ2=(00.39)2×0.75+(10.39)2×0.17+(20.39)×0.04+(30.39)2×0.025+(40.39)2×0.01+(50.39)2×0.005=0.114+0.063+0.103+0.170+0.130+0.106=0.686σ^2 = (0-0.39)^2 \times 0.75 + (1-0.39)^2 \times 0.17 + (2-0.39)^ \times 0.04 + (3-0.39)^2 \times 0.025 + (4-0.39)^2 \times 0.01 + (5-0.39)^2 \times 0.005 \\ = 0.114 + 0.063 + 0.103 + 0.170 + 0.130 + 0.106 \\ = 0.686

The standard deviation:

σ=σ2=0.686=0.828σ = \sqrt{σ^2} = \sqrt{0.686} = 0.828

The computed variance is 0.686 and standard deviation is 0.828 of the distribution.


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