Answer to Question #168191 in Statistics and Probability for Adrienne

Question

A coin tossed and die is rolled. The outcome of the coin is recoded "1" when it shows a head, and "0" when it shows a tail. The random variable gives the sum of the outcomes of coin and die. Compute the average value of the random variable?

Answer 1

$$\def\arraystretch{1.5} \begin{array}{c:c:c} & 1 & 0 \\ \hline 1 & 1+1=2 & 1+0=1 \\ \hdashline 2 & 2+1=3 & 2+0=2 \\ \hdashline 3 & 3+1=4 & 3+0=3 \\ \hdashline 4 & 4+1=5 & 4+0=4 \\ \hdashline 5 & 5+1=6 & 5+0=5 \\ \hdashline 6 & 6+1=7 & 6+0=6 \\ \end{array}$$

$$E(X)=mean=\dfrac{1}{12}(1)+\dfrac{2}{12}(2)+\dfrac{2}{12}(3)$$

$$+\dfrac{2}{12}(4)+\dfrac{2}{12}(5)+\dfrac{2}{12}(6)+\dfrac{1}{12}(7)=4$$

The average value of the random variable is 4.