Answer to Question #167824 in Statistics and Probability for Dhelany Castillo

Question

There are 10,000 sacks of rice. How many sacks of rice must be distributed to town A, B, and C if Town A has 15,000 families, Town B has 12,000, and Town C has 7,000?

Answer 1

Total stacks of rice $n=10,000$

Total no. of famalies $=15,000+12,000+7,000=34,000$

Probability of town A families $P_1=\dfrac{15000}{34000}=0.44117$

Probability of town B families $P_2=\dfrac{12000}{34000}=0.3529$41

Probability of town C families $P_3=\dfrac{7000}{34000}=0.20588$

Number of stacks distributed to town $A= P_1\times n=0.44176\times 10000=4411.76$

Number of stacks distributed to town $B= P_2\times n=0.352941\times 10000=3529.41$

Number of stacks distributed to town $C= P_3\times n=0.20588\times 10000=2058.8$