Question #167124

Three marbles are in a jar—one white, one blue and one green. Two marbles are picked one at a time with replacement. Let X be the number of blue marbles picked. Construct the probability distribution.


Expert's answer

Because we replace the first marble before selecting the second, the events are independent, so the probabilities are:

P(X=0)=23×23=49P(X=1)=23×13=29P(X=2)=13×13=19P(X=0) = \frac{2}{3} \times \frac{2}{3} = \frac{4}{9} \\ P(X=1) = \frac{2}{3} \times \frac{1}{3} = \frac{2}{9} \\ P(X=2) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}


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