There are 12 eggs in a pack. 4 are spoiled ones. If 2 of them are randomly selected, calculate the probability that at least one of them is faulty
At least means one or two spoiled eggs in this task. Consider the situation when we chose one spoiled egg. There are 4*8 = 32 variants (4 spoiled eggs for the first place and 8 remaining for the second). For the situation of two spoiled eggs there are (4*3)/2 = 6 variants (4 spoiled variants for the first place, 3 remaining spoiled eggs for the second, then divide by 2 because the order is not important). So the number of cases favorable for the event is 32 + 6 = 38. The number of total outcomes is 12*11/2 = 66 (12 variants for the first place, and 11 remaining variants for the second, and divide by 2 because the order is not important). The probability is 38/66 = 19/33.
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