Patients arrive at hospital accident and emergency at random at an average rate of 6 per hour. Find the probability that, during any 60-minute period, the number of patients arriving at the hospital accident and emergency department is at least 2. Round off answers to 4 decimal places.
This is a Poisson distribution with "\\lambda=6."
"P(X\\ge2)=1-P(X=0)-P(X=1)=1-e^{-6}(\\frac{6^0}{0!}+\\frac{6^1}{1!})=0.9827."
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