Answer to Question #161029 in Statistics and Probability for Sunny

Question #161029

As a policy of quick serving restaurant. A customer complaint needs to be attended immediately. On an average on a given day 4 customers complaints. Find the following probabilities.

A) P ( No complaints)

B) P ( At most 2 complaints)


1
Expert's answer
2021-02-24T07:36:17-0500

Poisson (X)=per 4 customer

the required probability P(x)=eμ×μnx!P(x)=\frac{e^{-\mu}\times \mu^n}{x!}

x>1 so

P(0)=e4×401=1e4P(0)=\frac{e^{-4}\times 4^0}{1}=\frac{1}{e^4}

Now, n=2

P(x)=e4×420!=16e4P(x)=\frac{e^{-4}\times 4^2}{0!}=\frac{16}{e^{4}}


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