Question #160671

800 students have a mean weight of 75 kg and standard deviation of 5kg. How many students weigh more than 80 kg


1
Expert's answer
2021-02-03T15:25:28-0500

Let XX be a random variable such that weight of the students, which is normally distributed with mean 7575 kg and standard deviation 55 kg.

Then we have μ=75\mu=75 and σ=5\sigma =5

Let us consider Z=XμσZ=\frac{X-\mu}{\sigma }. Then Z=X755Z=\frac{X-75}{5}

Now we have to find P(X>80)P(X>80)

P(X>80)=P(Z>80755)=P(Z>1)=0.5P(0<Z<1)\therefore P(X>80)=P(Z>\frac{80-75}{5})=P(Z>1)=0.5-P(0<Z<1)

=0.50.3413=0.5-0.3413 [P(0<Z<1)=0.3413[P(0<Z<1)=0.3413 from normal distribution table ]] =0.1587=0.1587


\therefore Number of students having weight more than 8080 kg is =80×P(X>80)=80×P(X>80)

=80×0.1587=80×0.1587

=127=127 (approximately)

Which is the required answer.


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