Answer to Question #16041 in Statistics and Probability for Chris Adams

Question

I am trying to figure out the math in order to calculate the probability that a slot machine will payout the players initial bet.

Betting 2 coins will make 1 spin. The probability that a minimum of 2 coins will be received:
I believe the math is:
Prob(E) = 1− Prob(NOT E)
Prob(2 or more coins) = 1 – ( Prob(0 coins) + Prob(1 coin) )
Prob(2 or more coins) = 1 – ( 0.168900 + 0.290615 )
Prob(2 or more coins) = 0.540485

Betting 6 coins will make 3 consecutive spins. What is the probability that a minimum of 6 coins will be received??

Betting 10 coins will make 5 consecutive spins. What is the probability that a minimum of 10 coins will be received??

The payouts are as follows for a single spin of the wheel:
0 Coins : 0.168900 1 coin : 0.290615 2 Coins : 0.380261 3 Coins : 0.055544 4 Coins : 0.061099 5 Coins : 0.016663 6 Coins : 0.011109 7 Coins : 0.005554 9 Coins : 0.000217 8 coins:n/a 10 Coins : 0.000435 more than 10 Coins : 0.009602