Question

A and B decided to meet between 3 PM, and 4 PM, each of them waits only 10 minutes. what is the probability that they will meet?

Answer 1

$$|x-y|\leq\dfrac{10}{60}$$

$P=1\times1-2(\dfrac{1}{2}\times(1-\dfrac{1}{6})\times(1-\dfrac{1}{6}))=\dfrac{11}{36}$

The probability that they will meet is $\dfrac{11}{36} .$