Question #154621

A group of students got the following scores in a test:6,9,12,15,18 and 21. Consider samples of size 3thag can be drawn from this population. List all the possible samples and the corresponding mean.


1
Expert's answer
2021-01-12T01:52:34-0500

There are a total of 20 combinations

The samples are

6,9,12



Mean=6+9+123=9Mean =\frac{6+9+12}{3} = 9

6,9,15



Mean=6+9+153=10Mean =\frac{6+9+15}{3} = 10

6,9,18



Mean=6+9+183=11Mean =\frac{6+9+18}{3} = 11

6,9,21



Mean=6+9+213=12Mean =\frac{6+9+21}{3} = 12

6,12,15



Mean=6+12+153=11Mean =\frac{6+12+15}{3} = 11

6,12,18



Mean=6+12+183=12Mean =\frac{6+12+18}{3} = 12

6,12,21



Mean=6+12+213=13Mean =\frac{6+12+21}{3} = 13

6,15,18



Mean=6+15+183=13Mean =\frac{6+15+18}{3} = 13

6,15,21



Mean=6+15+213=14Mean =\frac{6+15+21}{3} = 14

6,18,21



Mean=6+18+213=15Mean =\frac{6+18+21}{3} = 15

9,12,15



Mean=9+12+153=12Mean =\frac{9+12+15}{3} = 12

9,12,18



Mean=9+12+183=13Mean =\frac{9+12+18}{3} = 13

9,12,21


Mean=9+12+213=14Mean =\frac{9+12+21}{3} = 14

9,15,18



Mean=9+15+183=14Mean =\frac{9+15+18}{3} = 14

9,15,21



Mean=9+15+213=15Mean =\frac{9+15+21}{3} = 15

9,18,21



Mean=9+18+213=16Mean =\frac{9+18+21}{3} = 16

12,15,18



Mean=12+15+183=15Mean =\frac{12+15+18}{3} = 15

12,15,21



Mean=12+15+213=16Mean =\frac{12+15+21}{3} = 16

12,18,21



Mean=12+18+213=17Mean =\frac{12+18+21}{3} = 17

15,18,21



Mean=15+18+213=18Mean =\frac{15+18+21}{3} = 18


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