A mechanic performs MOT tests on cars to see if they are roadworthy, and only 75% of cars pass this test If 10 cars are tested one day, find the probability that 8 or more cars pass the test.
This is a binomial distribution with p=0.75,n=10.p=0.75, n=10.p=0.75,n=10.
P(X≥8)=P(X=8)+P(X=9)+P(X=10)=P(X\ge8)=P(X=8)+P(X=9)+P(X=10)=P(X≥8)=P(X=8)+P(X=9)+P(X=10)=
=C108∗0.758(1−0.75)2+C109∗0.759(1−0.75)1+C1010∗0.7510(1−0.75)0==C_{10}^8*0.75^8(1-0.75)^2+C_{10}^9*0.75^9(1-0.75)^1+C_{10}^{10}*0.75^{10}(1-0.75)^0==C108∗0.758(1−0.75)2+C109∗0.759(1−0.75)1+C1010∗0.7510(1−0.75)0=
=0.2816+0.1877+0.0563=0.5256.=0.2816+0.1877+0.0563=0.5256.=0.2816+0.1877+0.0563=0.5256.
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