Question #154500

If Z is a standard normal random variable, what is the value z for which P(0 ≤ Z ≤ z) = 0.35


1
Expert's answer
2021-01-11T15:35:46-0500

We have that P(0Zz)=0.35P(0 ≤ Z ≤ z) = 0.35

P(0Zz)=P(Zz)P(Z0)=P(Zz)0.5=0.35P(0 ≤ Z ≤ z) = P(Z\le z) - P(Z\le 0)=P(Z\le z)-0.5 = 0.35

Hence

P(Zz)=0.35+0.5=0.85    z=1.3P(Z\le z)= 0.35+0.5=0.85 \implies z = 1.3 from normal table we find corresponding z value


Answer: 1.3


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