If Z is a standard normal random variable, what is the value z for which P(0 ≤ Z ≤ z) = 0.35
We have that "P(0 \u2264 Z \u2264 z) = 0.35"
"P(0 \u2264 Z \u2264 z) = P(Z\\le z) - P(Z\\le 0)=P(Z\\le z)-0.5 = 0.35"
Hence
"P(Z\\le z)= 0.35+0.5=0.85 \\implies z = 1.3" from normal table we find corresponding z value
Answer: 1.3
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