If Z is a standard normal random variable, what is the value z for which P(0 ≤ Z ≤ z) = 0.35
We have that P(0≤Z≤z)=0.35P(0 ≤ Z ≤ z) = 0.35P(0≤Z≤z)=0.35
P(0≤Z≤z)=P(Z≤z)−P(Z≤0)=P(Z≤z)−0.5=0.35P(0 ≤ Z ≤ z) = P(Z\le z) - P(Z\le 0)=P(Z\le z)-0.5 = 0.35P(0≤Z≤z)=P(Z≤z)−P(Z≤0)=P(Z≤z)−0.5=0.35
Hence
P(Z≤z)=0.35+0.5=0.85 ⟹ z=1.3P(Z\le z)= 0.35+0.5=0.85 \implies z = 1.3P(Z≤z)=0.35+0.5=0.85⟹z=1.3 from normal table we find corresponding z value
Answer: 1.3
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