Question #153697

In a certain federal prison, it is known that 2/3 of the inmates are under 25 years of age. It is also known that 3/5 of the inmates are male and that 6/8 of the inmates are female or 25 years of age or older. What is the probability that a prisoner selected at random from this prison is female and at least 25 years old?


1
Expert's answer
2021-01-04T20:22:50-0500

Let A be the event which denotes that the inmates are under 25 years of age.

AC denotes that the inmates are at least 25 years of age.

P(A)=23P(AC)=1P(A)=123=13P(A) = \frac{2}{3} \\ P(A^C) = 1 -P(A) \\ = 1 -\frac{2}{3} \\ = \frac{1}{3}

Let M be the event which denotes that the inmate is male.

MC denotes that a inmate is female

P(M)=35P(MC)=1P(M)=135=25P(M) = \frac{3}{5} \\ P(M^C) = 1 -P(M) \\ = 1 -\frac{3}{5} \\ = \frac{2}{5}

Now, we have to find the probability that a prisoner selected at random from the prison is female at least 25 years old

P=13×25=215=0.1333P = \frac{1}{3} \times \frac{2}{5} \\ = \frac{2}{15} \\ = 0.1333

Answer: 0.1333


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