Question #15322 Given that event AAA and BBB are independent and that P(A)=1/8P(A) = 1/8P(A)=1/8 and P(A∪B)=1/3P(A \cup B) = 1/3P(A∪B)=1/3, find P(B)
Solution. Let P(B)=xP(B) = xP(B)=x, then P(A∩B)1/8xP(A \cap B) 1/8xP(A∩B)1/8x, so using inclusion-exclusion formula one can get 1/3=1/8+x−1/8x1/3 = 1/8 + x - 1/8x1/3=1/8+x−1/8x, thus x=5/21x = 5/21x=5/21.
Answer. 5/21.
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