"=\\dfrac{1}{13}(\\dfrac{1}{4})(\\dfrac{1}{13})=\\dfrac{1}{676}"
If the order is important
If the order is not important, there are 6 possible variants
"3!=6""(5, H, K), (5, K, H), (H, 5, K), (H,K,5),""(K,5,H),(K,H,5)"
"P=6(\\dfrac{1}{676})=\\dfrac{3}{338}\\approx0.0089"
c. 0.0015
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