Question #15222

Over a three year period in Smallsville, Judge Adams saw 37% of the cases, Judge Brown saw 39% of the cases and Judge Carter saw the remainder of the cases. Nine percent of Judge Adams' cases were appealed, 8% of Judge Browns's cases were appealed, and 6% of Judge Carters cases were appealed.

Given a randomly selected case from this three year period was not appealed, what is the probability the judge in the case was not Judge Carter?

Expert's answer

Question #15222 Over a three year period in Smallsville, Judge Adams saw 37% of the cases, Judge Brown saw 39% of the cases and Judge Carter saw the remainder of the cases. Nine percent of Judge Adams’ cases were appealed, 8% of Judge Browns’s cases were appealed, and 6% of Judge Carters cases were appealed.

Given a randomly selected case from this three year period was not appealed, what is the probability the judge in the case was not Judge Carter?

Solution. Denote by A,B,CA,B,C respectively respectively the events that random case was seen by Adams, Brown, Carter and by NANA the randomly selected case was not appealed. The condition implies that P(A)=0.37,P(B=0.39,P(C)=0.24)P(A)=0.37,P(B=0.39,P(C)=0.24) and P(NAA)=0.91,P(NAB)=0.92,P(NAC)=0.94P(NA|A)=0.91,P(NA|B)=0.92,P(NA|C)=0.94. We are to calculate P(CNA)=1P(CNA)P(\overline{C}|NA)=1-P(C|NA), using Bayesian formula one can get the last equals 1P(NAC)P(C)P(NAA)P(A)+P(NAB)P(B)+P(NAC)P(C)=10.940.240.910.37+0.920.39+0.940.2410.245=0.7551-\frac{P(NA|C)P(C)}{P(NA|A)P(A)+P(NA|B)P(B)+P(NA|C)P(C)}=1-\frac{0.94\cdot 0.24}{0.91\cdot 0.37+0.92\cdot 0.39+0.94\cdot 0.24}\approx 1-0.245=0.755.

Answer Approximately 0.76.

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