P(X=1)+P)X=2)+P(X=3)=1
k1+1+k2+1+k3+1=1\frac{k}{1+1}+\frac{k}{2+1}+\frac{k}{3+1}=11+1k+2+1k+3+1k=1
k(12+13+14)=1k(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})=1k(21+31+41)=1
k1312=1k\frac{13}{12}=1k1213=1
k=1213k=\frac{12}{13}k=1312
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