r=1−6∑d2n(n2−1)1-\frac{6\sum d^2}{n(n^2-1)}1−n(n2−1)6∑d2
d -4 0 -1 2 2 0 3 -2 -2 2
d2 16 0 1 4 4 0 9 4 4 4
=1−6∗(16+0+1+...+4)10(100−1)1-\frac{6*(16+0+1+...+4)}{10(100-1)}1−10(100−1)6∗(16+0+1+...+4)
=1−6∗4610∗991-\frac{6*46}{10*99}1−10∗996∗46
=0.7212
there is a strong positive relationship between the two judges.
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