Tourists enter a popular game reserve at an average rate of one every five minutes. What is the probability that exactly ten tourists arrive within the first hour?
P(X=10)=1210×e−1210!=0.104P(X = 10) = \frac{12^{10} \times e^{-12}}{10!} \\ = 0.104P(X=10)=10!1210×e−12=0.104
Answer: 0.104
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