X has the probability density function given below
p(x)={2(1−x)if 0≤x<10,otherwise p(x) = \begin{cases} 2(1-x) &\text{if } 0\le x < 1 \\ 0, &\text{otherwise } \end{cases}p(x)={2(1−x)0,if 0≤x<1otherwise
Find P(X≤2)P(X\le2)P(X≤2)
Solution
P(X<2)=1−P(X≥2)=1−0=1P(X<2) = 1-P(X\ge 2) = 1-0 = 1P(X<2)=1−P(X≥2)=1−0=1
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