X has the probability density function given below
"p(x) = \\begin{cases}\n 2(1-x) &\\text{if } 0\\le x < 1 \\\\\n 0, &\\text{otherwise }\n\\end{cases}"
Find "P(X\\le2)"
Solution
"P(X<2) = 1-P(X\\ge 2) = 1-0 = 1"
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