Let X be a life span of a bulb: X∼N(μ,σ2)
Then Z=σX−μ∼N(0,1)
Given μ=1025 h,σ=87 h
a)
P(X≥950)=1−P(X<950)
=1−P(Z<87950−1025)≈1−P(Z<0.862069)
≈1−0.194325=0.805675 b)
P(800<X<900)=P(X<900)−P(X≤800)
=P(Z<87900−1025)−P(Z<87800−1025)
≈P(Z<−1.436782)−P(Z<−2.586207)
≈0.075390−0.004852=0.070538
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