a) P(first engine use does not malfunction) = 1 - P(malfunction) = 1-0.0004 = 0.9996
b) P(first flight has no engine malfunctions) = (1 - P(malfunction))2 = 0.99962 = 0.9992
c) P(no engine malfunctions in first week) = (P(first flight has no engine malfunctions))6*7 = 0.999242 = 0.966945
d) P(at least one engine malfunction in first year) = 1-(P(first flight has no engine malfunctions))6*365 = 1-0.99922190 = 0.826695
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