The probability of an interval [a, b] , where -1 ≤ a ≤ 1 is 12(b−a)\frac{1}{2}(b-a)21(b−a)
P(B)=P(−0.5,1)=34P(A∩B)=P(−0.5,0)=14P(A∩C)=P(⊘)=0P(A∪B)=P(−1,1)=1P(A∪C)=P((−1,0)∪(0.75,1))=58P(A∪B∪C)=P(−1,1)=1P(B) = P(-0.5, 1) = \frac{3}{4} \\ P(A \cap B) = P(-0.5, 0) = \frac{1}{4} \\ P(A \cap C) = P(\oslash ) = 0 \\ P(A \cup B) = P(-1, 1) = 1 \\ P(A \cup C) = P((-1,0) \cup (0.75, 1)) = \frac{5}{8} \\ P(A \cup B \cup C) = P(-1,1) = 1P(B)=P(−0.5,1)=43P(A∩B)=P(−0.5,0)=41P(A∩C)=P(⊘)=0P(A∪B)=P(−1,1)=1P(A∪C)=P((−1,0)∪(0.75,1))=85P(A∪B∪C)=P(−1,1)=1
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