Answer to Question #148662 in Statistics and Probability for vladimyr lubin

Question

(Exa) 1.Find what is the probability of value of X being <= 110 for the Normal Distribution defined by average of 92, and standard deviation of 14.

2.What would be the probability of X being > 110. mean is 92 and st. deviation is 14 (Remember total probability is 1!!)

Answer 1

1.

$P(\le110)=P(Z\le \frac{110-92}{14})$

$=P(Z\le1.29)=0.9015$ from z tables

$P(\le110)=0.9015$

2.

$P(>110)=1-P(\le110)$

$=1-0.9015=0.0985$