Answer to Question #148459 in Statistics and Probability for Dipankar Roy

Question

Suppose that we have a fuse box containing 20 fuses, of which 5 are defective. If 2 fuses are
selected at random and removed from the box in succession without replacing the first, what is
the probability that both fuses are defective?

Answer 1

The probability that both fuses are defective is

$\frac{5}{20} \times \frac{4}{19} = \frac{1}{19} = 0.0526$

Answer: 0.0526