Question

Let N = 96000. From the intermittent signal 8:R
→
, we take samples -
10
where ke
EZ
. Under what conditions can the signal s be restored
from its samples? Also calculate this return formula
s(t) = . . .

Answer 1

You can use the normalized Whittaker – Shannon sample formula here

$s_1(t)=\sum_{k\in Z}s_1(k)sinc(t-k),$

where for the signal $s_1:R\to C$  applies $\bar s_1(v)=0$ whenever $|v|\geq1/2$