(a) Calculate the median of an Exponential(λ) random variable.
m - median value
F(m)=P(X≤m)=1−e−λm=1/2
From here
m=ln(2)/λ
(b) IfX∼Exponential(λ), what isP(X≤E(X))?
P(X≤E(x))=P(X≤1/λ)=1−e−λ∗1/λ=1−e−1=1−1/e=0.63
(c) My opinion that it is possible. Because the average value is not always equal to median
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