Q3=(34(n+1))th value of the observationn=50Q3=34(50+1)th value of the observation=(34(51))th value of the observation=38.25th value of the observationQ3=38th observation+0.25(39th−38th)=2.9+0.25(3.7−2.9)=2.9+0.25×0.8=2.9+0.2=3.1Q_3 = (\frac{3}{4}(n+1))^{th} \; value \; of \; the \; observation\\ n = 50 \\ Q_3 = \frac{3}{4}(50+1)^{th} \; value \; of \; the \; observation \\ = (\frac{3}{4}(51))^{th} \; value \; of \; the \; observation \\ = 38.25^{th} \; value \; of \; the \; observation \\ Q_3 = 38^{th} \; observation + 0.25(39^{th} - 38^{th}) = 2.9 + 0.25(3.7 - 2.9) \\ = 2.9 + 0.25 \times 0.8 \\ = 2.9+0.2 \\ = 3.1Q3=(43(n+1))thvalueoftheobservationn=50Q3=43(50+1)thvalueoftheobservation=(43(51))thvalueoftheobservation=38.25thvalueoftheobservationQ3=38thobservation+0.25(39th−38th)=2.9+0.25(3.7−2.9)=2.9+0.25×0.8=2.9+0.2=3.1
Answer: 3.1
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