The provided mean is
"\\lambda= 3"
a)We need to compute Pr(X=5). Therefore, the following is obtained using ti84,Pr(X=5)=0.10082
b)Using the Normal approximate to the Poisson distribution.
mean = "n*\\lambda" =5*3=15
sd= "\\sqrt{(n*\\lambda)}" ="\\sqrt{15}=" 3.873
Hence P(x=14)= =NORMSDIST((14.5-15)/SQRT(15))-NORMSDIST((13.5-15)/SQRT(15))=0.099372
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