Suppose the mean number of days to germination of a variety of seed is 22, with standard deviation 2.3 days. Find the probability that the mean germination time of a sample of 160 seeds will be within 0.5 day of the population mean.
Mean = 22
Sd = 2.3
Standard deviation of sampling distribution "= \\frac{Sd}{\\sqrt{n}}"
Standard deviation of sampling distribution "= \\frac{2.3}{\\sqrt{160}} = 0.1818"
Probability "= P(\\frac{-0.5 }{ 0.1818} < Z < \\frac{0.5}{0.1818})"
Probability = P(-2.75 < Z < 2.75)
Probability = P(Z < 2.75) – P(Z < -2.75) = 0.997 – 0.003 = 0.9940
Answer: 0.994
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