Let D represent departing on time and A represent arriving on time.
"P(D)=0.9"
"P(A)=0.8"
"P(D\\cap A)=0.75"
a. P(A|D)
"P(A|D)=\\frac{P(A\\cap D)}{P(D)}=\\frac{0.75}{0.9}=0.833"
b. "P(A|D^c)"
"P(D^c)=1-0.9=0.1"
"P(A\\cap D^c)=0.1-(1-0.9-0.8+0.75)=0.05"
"P(A|D^c)=\\frac{P(A\\cap D^c)}{P(D^c)}=\\frac{0.05}{0.1}=0.5"
c. The events departing on time and arriving on time are not independent. "P(A\\cap D)=0.75\\ne P(A)\u00d7P(D)=0.72"
Comments
Leave a comment