Question #145823
2. Patients arrive at a hospital accident and emergency department at random follow a Poisson distribution at a rate of 6 per hour.
(a) Find the probability that, during any 90-minute period, the number of patients arriving at the hospital accident and emergency department is
(i) exactly 7 (2 marks) (ii) at least 3 (2 marks)
(b) What is the mean and standard deviation of the number of patients arriving at the hospital accident and emergency department in an hour? (2 marks)
1
Expert's answer
2020-11-24T17:37:28-0500

Let X=X= the number of patients: XPo(λt)X\sim Po(\lambda t)


P(X=x)=eλt(λt)xx!P(X=x)=\dfrac{e^{-\lambda t}(\lambda t)^x}{x!}

(a) Given λ=6,t=1.5\lambda=6, t=1.5

(i)


P(X=7)=e9(9)77!0.11712P(X=7)=\dfrac{e^{-9}(9)^7}{7!}\approx0.11712

(ii)


P(X3)=1P(X=0)P(X=1)P(X=2)=P(X\geq3)=1-P(X=0)-P(X=1)-P(X=2)=

=1e9(9)00!e9(9)11!e9(9)22!==1-\dfrac{e^{-9}(9)^0}{0!}-\dfrac{e^{-9}(9)^1}{1!}-\dfrac{e^{-9}(9)^2}{2!}=

=150.5e90.9937678=1-50.5e^{-9}\approx0.9937678

(b)


mean=variance=λ=6mean=variance=\lambda=6

standard deviation=λ=62.44949standard \ deviation=\sqrt{\lambda}=\sqrt{6}\approx2.44949


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