Let "X=" the number of patients: "X\\sim Po(\\lambda t)"
(a) Given "\\lambda=6, t=1.5"
(i)
(ii)
"=1-\\dfrac{e^{-9}(9)^0}{0!}-\\dfrac{e^{-9}(9)^1}{1!}-\\dfrac{e^{-9}(9)^2}{2!}="
"=1-50.5e^{-9}\\approx0.9937678"
(b)
"standard \\ deviation=\\sqrt{\\lambda}=\\sqrt{6}\\approx2.44949"
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