Answer to Question #143916 in Statistics and Probability for Vladimyr Lubin

Question #143916
The table below displays results from experiments with polygraph instruments. Find the positive predictive value for the test. That​ is, find the probability that the subject​ lied, given that the test yields a positive result.

Did the Subject Actually​ Lie?
No​ (Did Not​ Lie) Yes​ (Lied)
Positive test results 20 40
Negative test results 32 11

The probability is (Round to 3 decimals)
1
Expert's answer
2020-11-29T18:02:11-0500

P(subject  lied  /test  yields  a  positive  result)=P(subject  lied  and  the  test  yields  a  positive  result)P(the  test  yields  a  positive  result)P(subject \; lied\;/test \;yields\; a \;positive\; result) = \frac{P(subject \; lied \; and \; the \; test \; yields \; a \; positive \; result)}{P(the\; test\; yields \;a \;positive\; result)}


=4310360103=4360=0.716= \frac{\frac{43}{103}}{\frac{60}{103}} = \frac{43}{60} = 0.716


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Comments

Assignment Expert
28.02.21, 14:06

Dear Ann, thank you for leaving a comment.

Ann
27.02.21, 11:22

= (40/103)/(60/103) = 40/60 = 0.666

Assignment Expert
25.02.21, 08:47

Dear Layla, please describe the answer you obtained in your solution.

Layla
24.02.21, 19:31

this work is wrong. I did the work (using the numbers I had) and the answer was incorrect but I did something else and it worked so dont follow this one

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