P(subject lied /test yields a positive result)=P(subject lied and the test yields a positive result)P(the test yields a positive result)P(subject \; lied\;/test \;yields\; a \;positive\; result) = \frac{P(subject \; lied \; and \; the \; test \; yields \; a \; positive \; result)}{P(the\; test\; yields \;a \;positive\; result)}P(subjectlied/testyieldsapositiveresult)=P(thetestyieldsapositiveresult)P(subjectliedandthetestyieldsapositiveresult)
=4310360103=4360=0.716= \frac{\frac{43}{103}}{\frac{60}{103}} = \frac{43}{60} = 0.716=1036010343=6043=0.716
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Dear Ann, thank you for leaving a comment.
= (40/103)/(60/103) = 40/60 = 0.666
Dear Layla, please describe the answer you obtained in your solution.
this work is wrong. I did the work (using the numbers I had) and the answer was incorrect but I did something else and it worked so dont follow this one
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Dear Ann, thank you for leaving a comment.
= (40/103)/(60/103) = 40/60 = 0.666
Dear Layla, please describe the answer you obtained in your solution.
this work is wrong. I did the work (using the numbers I had) and the answer was incorrect but I did something else and it worked so dont follow this one
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