"\\hat p=\\frac{100}{400}=0.4."
"95\\%CI=(\\hat p-z_{0.025}\\sqrt{\\frac{\\hat p(1-\\hat p)}{n}},\\;\\hat p+z_{0.025}\\sqrt{\\frac{\\hat p(1-\\hat p)}{n}})="
"=(0.4-1.96\\sqrt{\\frac{0.4(1-0.4)}{400}},\\;0.4+1.96\\sqrt{\\frac{0.4(1-0.4)}{400}})="
"=(0.2075,\\;0.2925)."
Ans. 5.
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