p^=100400=0.4.\hat p=\frac{100}{400}=0.4.p^=400100=0.4.
95%CI=(p^−z0.025p^(1−p^)n, p^+z0.025p^(1−p^)n)=95\%CI=(\hat p-z_{0.025}\sqrt{\frac{\hat p(1-\hat p)}{n}},\;\hat p+z_{0.025}\sqrt{\frac{\hat p(1-\hat p)}{n}})=95%CI=(p^−z0.025np^(1−p^),p^+z0.025np^(1−p^))=
=(0.4−1.960.4(1−0.4)400, 0.4+1.960.4(1−0.4)400)==(0.4-1.96\sqrt{\frac{0.4(1-0.4)}{400}},\;0.4+1.96\sqrt{\frac{0.4(1-0.4)}{400}})==(0.4−1.964000.4(1−0.4),0.4+1.964000.4(1−0.4))=
=(0.2075, 0.2925).=(0.2075,\;0.2925).=(0.2075,0.2925).
Ans. 5.
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