Question #143127
find the mean and the standard deviation of the heights of male engineering students in which the heights 66 inches and 75 inches correspond to standard scores of -0.6 and 1.1 respectively
1
Expert's answer
2020-11-09T19:52:58-0500

Given  that,y1=66,y2=75,Z1=0.6,Z2=1.1,thenZ=yμσ0.6=66μσ    0.6σ=66μ,1.1=75μσ    1.1σ=75μ,by multiplying the first equation by (-1) and then adding the result to the second equation1.7σ=66+75=9    σ=91.75.294,μ=66+0.6(5.294)=69.1764Given \;that,\\ y_{1}=66,y_{2}=75,Z_{1}=-0.6,Z_{2}=1.1,then\\ Z=\frac{y-\mu}{\sigma}\\ \therefore -0.6=\frac{66-\mu}{\sigma}\implies -0.6\sigma=66-\mu,\\ \therefore 1.1=\frac{75-\mu}{\sigma}\implies 1.1\sigma=75-\mu,\\ \text{by multiplying the first equation by (-1) }\\ \text{and then adding the result to the second equation}\\ 1.7 \sigma=-66+75=9\implies \sigma=\frac{9}{1.7}\approx 5.294,\\ \mu=66+0.6(5.294)=69.1764\\


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