From Z-table, P(Z<−1.57)=0.0582P(Z<-1.57)=0.0582P(Z<−1.57)=0.0582
Besides, the excel formula =NORM.S.DIST(-1.57,TRUE) yields the same answer. Thus the correct choice is 3.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments